If you never had a reason to feel bad for the One on “1 vs. 100″, now you have it. Brad Rutter is joining the mob. If you don’t know, Brad Rutter won over $3,000,000 on “Jeopardy!” and defeated Ken Jennings in the Ultimate Tournament of Champions, so if you go on “1 vs 100″ and you are up against him, dash away that hope at a million. However, with the tricky writing and quick time frame, could he be gone sooner than we think?
8 Responses to “Brad Rutter Joins “1 vs. 100″ Mob”
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Seeing him in the mob would make damned sure I’d take the money over the mob the moment I’d dodged the second question. That said, you’re right to point out the nature of the questions *really* favours the One over the Mob.
I dunno. Brad could get hit with another roulette question.
How do you say that the nature of the questions favours the One? The only advantage I see the One has would be the not-lifelines. Otherwise you could have any Mob member switch places with the One and their track record would be the same.
It’s not like Brad Rutter knows everything. Though he ranked as high as Ken Jennings brightness, he was just quicker at the buzzer. He has the same amount of chance to be eliminated. Let’s not forget that smarty-pants John Carpenter aint as smart as we think and Ken doesn’t know casino games. Brad might get a question wrong about… cartoons.
You gave a great example of why the One has the advantage: the roulette question. If you’re in the Mob, you have about five seconds to draw a mental picture of a roulette felt, see what color the number 1 is, and punch the button corresponding to your choice. Not confident? Just pick an answer and cross your fingers. If you’re the One, you have all the time you could possibly need to try and draw that mental picture.
Maybe this is why the top prize is $3 million for this episode only (i.e., join the Brad Rutter club).
Oh now that actually makes some sense.
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